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Displaying Source Code(s)
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Number Magic in C.
--------------------------------------------------------------------------------
Description : It seems to be a illusion, but it involves
complete mathematics logic. You are required to think a number
between a given range, just think in your mind and don't enter
the number. And my program will find out that number by just
answering few questions. So just try it......have fun!
#include<stdio.h>
#include<conio.h>
int generate(void);
int fun(int);
void main()
{
int i,a,r;
clrscr();
gotoxy(30,12);
printf("Harsh Welcomes You!
IN THE JARGON OF A NUMBER..");
printf("
Press any key to continue....");
getch();
clrscr();
gotoxy(15,8);
printf("Just think a number between 1 to 63 in your mind");
printf("
Think on one
");
printf("Do not enter that number");
printf("
I will find that number on your mind....");
printf("
Press any key to continue...");
getch();
clrscr();
gotoxy(20,7);
printf("By Just answering few questions....");
printf("
If your number is present in the numbers");
printf(" shown on your screen,
Then press P and if not present");
printf(" then press N
");
printf(" But please be honest while entering the answer...");
printf("
Press any key to continue...");
getch();
clrscr();
r=generate();
if(r==0)
{
gotoxy(20,11);
printf("You didn't think of any number between 1 to 63");
printf("
So try again...");
}
else
{
gotoxy(30,11);
printf("Your number is %d",r);
printf("
Surprised! But friends it is not a magic,");
printf(" it just involves some mathematical computation....");
printf(" so guys just try to find out the method.
");
printf(" Thank You!
");
printf(" Programmed By:
Harsh Birla");
}
getch();
}
int generate()
{
int a,i,j,f,num[6],n,r=0;
char ch[6];
for(j=0;j<=5;j++)
{
gotoxy(1,7);
f=fun(j);
for(i=1;i<=63;i++)
{
//f=fun(j);
//printf("%d",f);
a=i & f;
if(a==f)
//gotoxy(5,10);
printf(" %d",i);
}
printf("
Let me remind you if the number is present then");
printf(" press P otherwise press N");
printf("
Enter your answer: ");
ch[j]=getche();
printf("
Press any key to continue....");
//clrscr();
if(ch[j]=='p' || ch[j]=='P')
{
num[j]=1;
n=fun(j);
r=r+n;
}
else
num[j]=0;
getch();
clrscr();
}
/* for(j=5;j>=0;j--)
{
printf("%d",num[j]);
// if(ch[j]=='p' || ch[j]=='P')
// num[j]=1;
// else
// num[j]=0;
} */
// printf("
%d",r);
return r;
}
int fun(int j)
{
if(j==0)
return 1;
else
return 2*fun(j-1);
}
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123
Eng