CTS Job Placement Paper
COGNIZANT (CTS)
There wer 5 section 8 questions each (40 q totally) 60 minute 5 different
sets of question papers 1 Mark each
0.25 negative marking
CTS BLACK
Vocabulary, strings, dominoes, functions, coding (each section 8 ques)
CTS BROWN
Word series, numerical series, functions, figures, verbal (each section 8
ques)
CTS VIOLET
Functions, strings, bricks, jigsaw puzzle, cryptic clues (each section 8
ques)
CTS RED
1) 8 functions 2) 4 cryptic clues, 4 anagrams
3) 4 Tetris figures, 4 bricks 4) 8 strings 5) 4 jigsaw puzzles 4 number
series
BROWN 2002
There were different papers for different sessions.The paper had 5 sections,
5 * 8 = 40 Que's. totally
--------------------------------------------------------------------------------
Section 1: Functions
Q: 1 - 8
Certain functions were given & based upon the rules & the choices had to be
made based on recursion. This is time consuming, but u can do it. Try to do
it at the end. Start from the last section.
L(x) is a function defined. functions can be defined as
L(x)=(a,b,ab) or (a,b,(a,b),(a,(b,b)),a,(b,b)).... two functions were given
A(x) & B(x) like
if l(x)=(a,b,c) then A(x)=(a) & B(x)=(b,c)
i.e., A(x) contains the first element of the function only.& B(x) contains
the remaining, except the first element.
then the other two functions were defined as
C(x) = * if L(x) = ()
A(x) if L(x) = () & B(x) != () & C(B(x)) otherwise
D(x) = * if L(x) = ()
** if B(x) = ()
A(x), if L(x) != () & B(x) != ()
D(D(x)),otherwise ;
Now the Questions are,
1 : if L(x) = (a,b,(a,b)) then C(x) is ?
(a): a (b): b (c): c (d): none
2 : if L(x) = (a,b,(a,b)) then find D(x)
same options as above
3 : if L(x) = (a,b,(a,b),(b,(b))) find C(x)
4 : find D(x)
5 : if L(x) = (a,(a,b),(a,b,(a,(b))),b) then find c(x)
6 : find D(x)
7 : if L(x) = (a,b,(a,b)) then find C(D(x))
8 : find D(C(x))
Section 2: Word series
Q’s: 9 - 16
If S is a string then p, q, r forms the sub strings of S. For eg, if S =
aaababc & p = aa,q = ab, r =bc . Then on applying p à q on S is that
ababaabc. Only the first occurrence of S has to be substituted. If there is
no sub string of p, q, r on s then it should not be substituted.If S =
aabbcc, R = ab, Q = bc. Now we define an operator R 
Q when operated on S, R is replaced by Q, provided Q is a subset of S,
otherwise R will be unchanged. Given a set S =… when R Q, P= =
672; R, Q  P operated successively on S, what will be new S? There
will be 4 =: if s = aaababc & p = aa, q = ab, r = bc then applying p à q, q
à r & r à p will give,
(a): aaababc (b): abaabbc (c): abcbaac (d): none of the a,b,c
10: if s = aaababc & p = aa q = ab r = bc then applying q à r & r à p will
give,
11: if s = abababc & p = aa q = ab r = bc then applying p à q, q à r & r à p
will give,
12: if s = abababc & p = aa q = ab r =bc then applying q à r & r à p will
give,
13: if s=aabc & p=aa q=ab r=ac then applying p->q(2) q->r(2) r->p will
give,(2) Means applying the same thing
twice.
14: Similar type of problem.
15) if s = abbabc p = ab q = bb r = bc then to get s = abbabc which one
should be applied.
(a): p->q,q->r,r->p
16) if s = abbabc p = ab q = bb r = bc then to get s = bbbcbabc which one
should be applied.
Let us consider a set of strings such as S = aabcab. We now consider two
more sets P and Q that also contain strings. An operation Pà Q is defined in
such a manner that if P is a subset of S, then P is to be replaced by Q. In
the following questions, you are given various sets of strings on which you
have to perform certain operations as defined above. Choose the correct
alternative as your answer.(Below are some ques from old ques papers)
a) Let S = abcabc, P = bc, Q = bb and R = ba. Then P à Q, Q à R and R à P,
changes S to
________? (A) ............ (B) abcabc (C) ............ (D) none of A, B, C
b) Let S = aabbcc, P = ab, Q = bc and R = cc. Then P à Q, Q à R and R à P,
changes S to
_________? (A) ababab (B) ............ (C) ............ (D) none of A, B, C
c) Let S = bcacbc, P = ac, Q = ca and R = ba. Then P à Q, Q à R, P à R and
changes S to
________? (A) ............ (B) ............ (C) bcbabc (D) none of A,B,C
d) Let S = caabcb, P = aa, Q = ca and R = bcb. Then P à Q, P à R, R àQ and
changes S to
________?
(A) ............ (B) ............ (C) ............ (D) none of A,B,C
Section 3: numerical series
17: 2,20,80,100…
(a): 121, (b): 116 (c): (d):none
18: 10,16,2146,2218…
|